Varargs with different type parameters in scala -

i'm new scala...

anyway, want like:

val bar = new foo("a" -> list[int](1), "b" -> list[string]("2"), ...) bar("a") // gives list[int] containing 1 bar("b") // gives list[string] containing "2" 

the problem when do:

class foo(pairs: (string, list[_])*) {   def apply(name: string): list[_] = pairs.tomap(name) } 

pairs gonna array[(string, list[any]) (or that) , apply() wrong anyway since list[_] 1 type instead of "different types". if varargs * returned tuple i'm still not sure how i'd go getting bar("a") return list[originaltypepassedin]. there way of doing this? scala seems pretty flexible feels there should advanced way of doing this.

this can't done. consider this:

val key = readstringfromuser(); val value = bar(key); 

what type of value? depend on user has input. types static, they're determined , used @ compile time.

so you'll either have use fixed number of arguments know types @ compile time, or use generic vararg , type casts during runtime.