How do I strip a string given a list of unwanted characters? Python -

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is there way pass in list instead of char str.strip() in python? have been doing way:

unwanted = [c c in '!@#$%^&*(fghjkmn'] s = 'ffffofob*&%ar**^' u in unwanted:   s = s.strip(u) print s

desired output, output correct there should sort of more elegant way how i'm coding above:

ofob*&%ar

strip , friends take string representing set of characters, can skip loop:

>>> s = 'ffffofob*&%ar**^' >>> s.strip('!@#$%^&*(fghjkmn') 'ofob*&%ar'

(the downside of things fn.rstrip(".png") seems work many filenames, doesn't work)


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