How do I open up a text file and use it in this code to sort ip adresses python -

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so instead of setting ips sort through have plethora of them in text file need sort though how open , see ones occurred most?

#!/usr/bin/python  import iplib  ips = []  ip in ["192.168.100.56", "192.168.0.3", "192.0.0.192", "8.0.0.255"]:        ips.append(iplib.ipv4address(ip))  def ip_compare(x, y):        return cmp(x.get_dec(), y.get_dec())  ips.sort(ip_compare)  print [ip.address ip in ips]

and text file looks this

113.177.60.181 - - [05/jul/2013:03:27:07 -0500] "get /email/13948staticvoid.gif http/1.1" 200 17181 "http://www.bereans.org/email/index.php" "mozilla/4.0 (compatible; msie 8.0; windows nt 5.1; trident/4.0)" 113.177.60.181 - - [05/jul/2013:03:27:07 -0500] "get /email/13948staticvoid.gif http/1.1" 200 17181 "http://www.bereans.org/email/index.php" "mozilla/4.0 (compatible; msie 8.0; windows nt 5.1; trident/4.0)" 

from collections import counter open('path/to/file') infile:     counts = counter(line.split('-', 1)[0].strip() line in infile) ips = counts.most_common() # @jon clements # equivalent ips = sorted(counts, key=counts.__getitem__, reverse=true)

there go! ips has list of ip addresses in text file, sorted in order frequent least frequent


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