PHP Jquery JSON catching -

-

here's php responding jquery calls.

<?php    if ( isset( $_post['icnumber']) && $_post['icnumber'] != '' ) {     $custic = $_post['icnumber'];     $response = array();     $response['status'] = 'false';     $sql ="select * ctrl_cust cust_ic='$custic'";     $raw = mysql_query($sql,$link) or die('query 1 '.mysql_error());     if ( $data = mysql_fetch_assoc( $raw ) ) {        $response['status'] = 'true';        $response['custid'] = $data['cust_id'];        $response['custname'] = $data['cust_name'];     }     header("content-type: application/json", true);     echo json_encode($response);     } ?>

and here's jquery

$(function() {     $('#icnumber-form').submit(function() {                var icno  = $('#icnumber').val();         $.ajax({            type    : 'post',            url     : 'php/create_process.php',            data    : icno,            datatype: 'json',            success : function(data){                console.log(data);                         },            beforesend:function(){                $('.cust-exist-view').fadein();            }        });        return false;     }) });

the thing is, console.log returns null, when submit form without javascript enabled, returns :

{"status":"true","custid":"00001","custname":"john"}

i wonder problem...i've been running around in circles hours...help me please?

icnumber not getting post, change data: icno, data: {icnumber: icno}, , try


Comments

Post a Comment

Popular posts from this blog

html5 - What is breaking my page when printing? -

-
Image
i have questioner , don't know why when printing it's creating break before first question. live demo (link) i able resolve issue removing fieldset container had wrapped in.. having fieldset element causing of fields grouped together, , since not fit on first page, being pushed second page. removing fieldset element, able firefox print first 2 questions on page 1 identically chrome. it seems not new problem firefox , fieldset not playing nice found old bugzilla ticket 2008 has persisted , still being commented on in 2014 (link) if retaining fieldset important, found solution else came here (link) <script type='text/javascript'> $(window).bind('beforeprint', function(){ $('fieldset').each( function(item) { $(this).replacewith($('<div class="fieldset">' + this.innerhtml + '</div>')); } ) }); $(window).bind(
Read more

c# - must be a non-abstract type with a public parameterless constructor in redis -

-
when save object, got below error must non-abstract type public parameterless constructor in order use parameter 't' in generic type or method 'servicestack.redis.redisclient.store<t>(t) redisclass.getinstnace().store(msg); // error here redisclass.getinstnace().save(); as third party's class, can not edit how save object? could create wrapper around third party object call constructor, store wrapper? e.g. public class mywrapper { public thirdpartyobject thirdpartyinstance { get; set; } public mywrapper() { thirdpartyinstance = new thirdpartyobject("constructors"); } }
Read more

ajax - PHP/JSON Login script (Twitter style) not setting sessions -

-
i'm having trouble getting twitter style login work properly, reason gets stuck at session_register("useremail"); session_register("userpass"); and doesn't redirect after it. if enter wrong account data, works , appropriate error message pops up. this full code: <?php if(empty($_post['email']) || empty($_post['password'])) { die(msg(0,"all fields required")); } if(!(preg_match("/^[\.a-z0-9_\-\+]+[@][a-z0-9_\-]+([.][a-z0-9_\-]+)+[a-z]{1,4}$/", $_post['email']))) die(msg(0,"you haven't provided valid e-mail")); $host="localhost"; $username="root"; $password="x"; $db_name="x"; $tbl_name="x"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select db"); $useremail=$_post['email']; $userpass=
Read more