sorting - Javascript sort method -

-

i working bit of code on website , trying order results member id (i've left comments in code below is) doesnt seem sort order of results though guess must doing wrong. know issue is, , perhaps how limit amount of results shown 10 please?

var httprequestobject = $.ajax({ type: "post", contenttype: "application/json; charset=utf-8", url: "/wcf/search.svc/testsearch", datatype: "json", success: function (response) {      if (response != null && response.d != null) {         var data = response.d;         if (data.serviceoperationoutcome == 10) {              var profilelist = data.memberlist;             if (profilelist != null && profilelist.length > 0) {                 (var = 0; < profilelist.length; i++) {                     var profile = profilelist[i];                      // sort var                     var memberid = (profile.memberid);                       if (profile != null) {                         var clonedtemplate = $('.profile-slider #profile').clone();                         $(clonedtemplate).removeattr('style').removeattr('id');                         $(clonedtemplate).find('img').attr("src", profile.thumbnailurl).attr("alt", profile.nickname).wrap('<a></a>');                         $(clonedtemplate).appendto('.profile-slider');                          // sort                         $(memberid).sort();                     }                 }              }         }          else {             alert("error code " + string(data.serviceoperationoutcome));         }     }      else {         alert("null data");     } },  error: function (jqxhr, textstatus, errorthrown) {     alert(errorthrown); }

});

as adeneo said, want sort member list.

profilelist = profilelist   .filter(function (arg) {return arg !== null;}) // remove nulls   .sort(function(a, b) {     return a.memberid < b.memberid ? -1 : 1; // < operator works numbers or strings   });

Comments

Post a Comment

Popular posts from this blog

html5 - What is breaking my page when printing? -

-
Image
i have questioner , don't know why when printing it's creating break before first question. live demo (link) i able resolve issue removing fieldset container had wrapped in.. having fieldset element causing of fields grouped together, , since not fit on first page, being pushed second page. removing fieldset element, able firefox print first 2 questions on page 1 identically chrome. it seems not new problem firefox , fieldset not playing nice found old bugzilla ticket 2008 has persisted , still being commented on in 2014 (link) if retaining fieldset important, found solution else came here (link) <script type='text/javascript'> $(window).bind('beforeprint', function(){ $('fieldset').each( function(item) { $(this).replacewith($('<div class="fieldset">' + this.innerhtml + '</div>')); } ) }); $(window).bind(
Read more

c# - must be a non-abstract type with a public parameterless constructor in redis -

-
when save object, got below error must non-abstract type public parameterless constructor in order use parameter 't' in generic type or method 'servicestack.redis.redisclient.store<t>(t) redisclass.getinstnace().store(msg); // error here redisclass.getinstnace().save(); as third party's class, can not edit how save object? could create wrapper around third party object call constructor, store wrapper? e.g. public class mywrapper { public thirdpartyobject thirdpartyinstance { get; set; } public mywrapper() { thirdpartyinstance = new thirdpartyobject("constructors"); } }
Read more

ajax - PHP/JSON Login script (Twitter style) not setting sessions -

-
i'm having trouble getting twitter style login work properly, reason gets stuck at session_register("useremail"); session_register("userpass"); and doesn't redirect after it. if enter wrong account data, works , appropriate error message pops up. this full code: <?php if(empty($_post['email']) || empty($_post['password'])) { die(msg(0,"all fields required")); } if(!(preg_match("/^[\.a-z0-9_\-\+]+[@][a-z0-9_\-]+([.][a-z0-9_\-]+)+[a-z]{1,4}$/", $_post['email']))) die(msg(0,"you haven't provided valid e-mail")); $host="localhost"; $username="root"; $password="x"; $db_name="x"; $tbl_name="x"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select db"); $useremail=$_post['email']; $userpass=
Read more